# GSLB ZONE AS A RECORD

**URL:** <https://community.a10networks.com/t/gslb-zone-as-a-record/795>\
**Category:** ADC - Application Delivery\
**Tags:** gslb\
**Created:** [August 23, 2023, 5:05pm UTC](https://community.a10networks.com/t/gslb-zone-as-a-record/795 "2023-08-23T17:05:04Z")\
**Posts on this page:** 2\
**Page:** 1

<div class="post-metadata">

**Author:** ![anfovar](https://avatars.discourse-cdn.com/v4/letter/a/bc79bd/32.png) [@anfovar](https://community.a10networks.com/u/anfovar)\
**Post date:** [August 23, 2023, 5:05pm UTC](https://community.a10networks.com/t/gslb-zone-as-a-record/795/1 "2023-08-23T17:05:04Z")

</div>

Hello!  
I´m configuring GSLB with a challenge which is to answer the queries for [example.com](http://example.com) as A record.  
[example.com](http://example.com) → x.x.x.x  
The thing is that when we configured GSLB we have to add the domain in the zone and then configure the services for example [www.example.com](http://www.example.com)

Does someone know how can I do this?

---

<div class="post-metadata">

**Author:** ![mdunn](https://avatars.discourse-cdn.com/v4/letter/m/87869e/32.png) [@mdunn](https://community.a10networks.com/u/mdunn)\
**Post date:** [August 29, 2023, 3:07am UTC](https://community.a10networks.com/t/gslb-zone-as-a-record/795/2 "2023-08-29T03:07:01Z")

</div>

You can create a service without a name. From CLI, do not enter a service name after the port, and from the GUI, do not enter a service name in the text field. This will create a FQDN for the gslb zone name.

**CLI** :

```yaml
gslb zone gslb.dunnlab.com
  service 443
    dns-a-record web2 ttl 0 static

```

**GUI** 1. :  
GSLB \> FQDNS \> Create

1. Select Existing Zone. Leave Service field empty. Enter Port #. Create.
2. Edit the new FQDN. Create Service A Record. Update FQDN

Hope this helps!
